Posted by **Pretender** on Tuesday, March 12, 2013 at 5:19am.

When a man in a cage whose weight is 1000N pulls a rope that is attached on a cage around a fixed pulley,the force he exerts on the floor of the cage is 450N ,if the cage weigh 250N ,find the acceleration

- Physics -
**bobpursley**, Tuesday, March 12, 2013 at 5:42am
I dont get the picture...a man in a cage pulls a rope attached to the cage..

- Physics -
**Pretender**, Tuesday, March 12, 2013 at 6:08am
Picture it like this:the rope is attached on top of the cage then from there it passes around a fixed pulley so the man in the cage is pulling the rope down from the pulley.PLEASE HELP ME Bobpursley

- Physics -
**drwls**, Tuesday, March 12, 2013 at 6:08am
The weight of cage + man is 1250 N and their combined mass is

Mtotal = Wtotal/g = 127.6 kg.

The man and cage accelerate at the same rate, a. Let F be the rope tension force. Consider all forces on the man, including weight and the upward floor force. The man's mass is 102 kg

F - Wman + 450 = F - 550 = 102*a

Now consider all exernal forces on man and cage together:

F -1250 = 127.6 a

Combining the two results in

700 = -25.6 a

a = -0.0366 m/s^2

- Physics -
**Manoj**, Friday, August 26, 2016 at 8:55pm
I think u have to also take

T-f-Wchair=McA

- Physics -
**Manoj**, Friday, August 26, 2016 at 9:01pm
U did a mistake

Wtotal/g=127.55

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