Thursday
March 23, 2017

Post a New Question

Posted by on Monday, March 11, 2013 at 2:12pm.

A saline solution contains 1.1% NaCl by mass. How much NaCl is present in 87.2 g of this solution?

  • chemistry - , Monday, March 11, 2013 at 2:24pm

    This is not the answer but it the same thing:

    1.3 g / 100 g = 0.013.
    0.013 * 89.2 g = 1.1596 g
    = 1.16 g.

  • chemistry - , Monday, March 11, 2013 at 3:19pm

    Or, another way.
    1.1% w/w means 1.1g NaCl in 100 g solution.
    You want to know how much is there in 87.2 g (and not 100g); therefore,
    1.1 x (87.2/100) = ?

  • chemistry - , Saturday, March 16, 2013 at 6:23pm

    A 5.00-ml sample of a H3PO4 solution of unknown concentration is titrated with a 0.1003 M NaOH solution. A volume of 6 .55ml of the Na OH solution was required to reach the endpoint. What is the concentration of the unknown H3PO4 solution?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question