Posted by please help Ms.Sue!!!! on Monday, March 11, 2013 at 4:38am.
At a museum, ticket prices are $13 for adults and $11 for children. If a tour group paid $179 for their tickets, how many people were in the tour group?

algebra!!!  Lena, Monday, March 11, 2013 at 5:41am
I'm not Ms. Sue but I could try to help. Let's create a formula:
Let A denote the # of adult tickets
Let C denote the # of child tickets
Therefore...
$13 x A + $11 x C = $179
13A + 11C = 179
So from this point forward, I would ask the following. What # must you subtract from $179 in order for it be divisible by 11. That number must also be a factor of 13.
Essentially what I'm saying is 11C = 17913A
The answer to that would be the following:
13 x 7 = 91
179 91 = 88
88/11  8
Therefore, 7 adults and 8 kids.
PS  You could do it the other way around where you could try to find the number divisible by 179 which is also a factor of 11 but I thought it would be easier to do it the other way around since we're more familiar with our 11 times tables.
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