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November 23, 2014

November 23, 2014

Posted by **please help Ms.Sue!!!!** on Monday, March 11, 2013 at 4:38am.

- algebra!!! -
**Lena**, Monday, March 11, 2013 at 5:41amI'm not Ms. Sue but I could try to help. Let's create a formula:

Let A denote the # of adult tickets

Let C denote the # of child tickets

Therefore...

$13 x A + $11 x C = $179

13A + 11C = 179

So from this point forward, I would ask the following. What # must you subtract from $179 in order for it be divisible by 11. That number must also be a factor of 13.

Essentially what I'm saying is 11C = 179-13A

The answer to that would be the following:

13 x 7 = 91

179- 91 = 88

88/11 - 8

Therefore, 7 adults and 8 kids.

PS - You could do it the other way around where you could try to find the number divisible by 179 which is also a factor of 11 but I thought it would be easier to do it the other way around since we're more familiar with our 11 times tables.

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