Posted by please help Ms.Sue!!!! on Monday, March 11, 2013 at 4:38am.
I'm not Ms. Sue but I could try to help. Let's create a formula:
Let A denote the # of adult tickets
Let C denote the # of child tickets
Therefore...
$13 x A + $11 x C = $179
13A + 11C = 179
So from this point forward, I would ask the following. What # must you subtract from $179 in order for it be divisible by 11. That number must also be a factor of 13.
Essentially what I'm saying is 11C = 179-13A
The answer to that would be the following:
13 x 7 = 91
179- 91 = 88
88/11 - 8
Therefore, 7 adults and 8 kids.
PS - You could do it the other way around where you could try to find the number divisible by 179 which is also a factor of 11 but I thought it would be easier to do it the other way around since we're more familiar with our 11 times tables.
Related Questions
maths - Tickets for the Universal Studios amusement park are priced at $32 for ...
Algebra - Could someone please help me with this word problem? The City Zoo has ...
ALG2! WORD PROBLEM!very important!! - There are two adults and three children (...
Algebra - One adults ticket to an amusement park costs d dollars. One child'...
Algebra - A theater ticket for adults is a dollars and the price of a child'...
math - Please show work The little town arts center charges $21 for adults, $17 ...
Chicago Virtual Charter School - A movie theater charges $7 for adults, $5 for ...
Algebra - Write the answer to the problem as an algebraic expression. A theater ...
ALG2! WORD PROBLEM! PLZ HELP!! - A family of 5 comes to the amusement park. ...
Algebra 2 - At a county fair, adults' tickets sold for $5.50, senior ...
For Further Reading