Wednesday

September 17, 2014

September 17, 2014

Posted by **Anonymous** on Monday, March 11, 2013 at 12:02am.

(a) What is the impedance of the circuit?

- physics -
**Henry**, Wednesday, March 13, 2013 at 3:33pmR = 42 Ohms.

Xc = 1/W*C = 1/(140*175*10^-6)=40.8 Ohms

Xl = W*L = 140*100*10^-3 = 14 Ohms.

Z^2 = R^2 + (Xl-Xc)^2 = 2482.24

Z = 49.82 Ohms.

tanA = (Xl-Xc)/R = (14-40.8)/42=-0.63810

A = -32.54o = Phase angle.

Z = 49.82 Ohms @ -32.54o.

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