Tuesday

March 31, 2015

March 31, 2015

Posted by **Lisa** on Sunday, March 10, 2013 at 7:46pm.

I took the second derivative and solved for zeros. I got x=-1 and x=1. However when plugged into the orig. equation this results in 4/0 (undefined). Does this mean there is no concavity?

- Concavity-Calculus -
**Steve**, Sunday, March 10, 2013 at 8:46pmif f = 4/(x^2-1)

f'' = 8(3x^2+1)/(x^2-1)^3

f'' is never zero.

f'' is discontinuous at x=1 and -1, and changes sign there

so, f ix concave down for |x|<1 and concave up for |x|>1

**Answer this Question**

**Related Questions**

Please check my Calculus - 1. Find all critical values for f(x)=(9-x^2)^⅗ ...

Math-Calculus (check please) - FOr the function f(x)=x^2e^x Find the critical ...

CALC 1 - Suppose that h is a function with h'(x) = xe^x. Find all intervals ...

Math - How would you write open intervals for concavity? After you find the ...

Please check my Calculus - 1. Given f(x)=-6/x, choose the correct statement A. ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Calculus - f(x)= x/(1+x)^2 a) find the intervals on which f is increasing or ...

math - The section is on concavity and the second derivative test, the question ...

Please check my Calculus - 1. Find the value(s) of c guaranteed by Rolle’s ...