Posted by Ashley on .
For the reaction 2A(g) + B(aq) + 3C(l)<------> D(s) + 3E(g), the concentrations at equilibrium are found to be:
A: 2.3x10^3 Pa
B: 1.8x10^-2 M
E: 5.6x10^4 Torr
Find the numerical value of the equilibrium constant that would appear in a conventional table of equilibrium constants.
Solids and liquids don't count for Keq; therefore,
Keq = (E)^3/(A)^2(B)
Substitute those values from the problem and solve for Keq.
for my answer i got 597559.1682 is this correct??
The problem is misleading. It says the numbers "below" are concentrations but they aren't. A is in pascals; although pressure and M can be mixed, pascals must be converted to atmospheres. 101325 Pa = 1 atm. Likewise, E is in torr and must be converted to atm. 760 torr = 1 atm.