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Calculus

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Evaluate \displaystyle \int_1^{10} \left(\sqrt{x} + 1\right)^3 dx - \int_1^{10} \left(\sqrt{x} - 1\right)^3 dx .

  • Calculus -

    Hint:

    For x > 0, you have

    (sqrt(x) + 1)^3 - (sqrt(x) - 1)^3 =

    6 x + 2

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