Calulus
posted by John on .
Given \displaystyle \int_0^{\frac{3\pi}{2}} x^2\cos x \, dx = a  \frac{b\pi^2}{c}, where a, b and c are positive integers and b and c are coprime, what is the value of a + b + c?

Man, can you cut the T_{E}X?
I think you have
∫[0,3π/2] x^2 cosx dx = a  bπ^2/c
well, that's 2  9/4 π^2, so
(a,b,c) = (2,9,4), so a+b+c=15