Thursday

October 23, 2014

October 23, 2014

Posted by **Ed** on Sunday, March 10, 2013 at 11:46am.

I'm not looking for a solution which includes Potential Energy. We haven't learned that in class yet, is there a another way to solve this?

- Physics -
**Damon**, Sunday, March 10, 2013 at 1:19pmThe energy way is the easy way but.

Normal force = m g cos 14

force down ramp = m g sin 14 + mu m g cos 14 = m g (mu cos 14+ sin 14)

= m g ( 1.12 )

F = m a

a = F/m = g (1.12) = 10.9 m/s^2 down ramp

say t is time to stop

v = Vi - 10.9 t

0 = Vi - 10.9 t

so

t = Vi/10.9

d = Vi t - (10.9/2) t^2

85 = Vi^2/10.9 - (10.9/2)(Vi/10.9)^2

85 = (Vi^2/10.9 )( 1 - 1/2)

170 = Vi^2/10.9

Vi = 43 m/s

**Answer this Question**

**Related Questions**

Physics - A car with engine trouble slides 85 meters up along a 14 degrees ramp ...

Physics - Starting from rest, a 11.50 kg suitcase slides 3.18 m down a ...

physics - Starting from rest, a 10.7 kg block slides 2.60 m down to the bottom ...

ap physics - Starting from rest, a 10.2 kg block slides 2.90 m down a ...

physics - A 20 kg block slides with an initial speed of 11 m/s up a ramp ...

Physics - A car is moving with a velocity of 16 m/s when the brakes are applied ...

physics - An 8.65-kg block slides with an initial speed of 1.52 m/s up a ramp ...

Physics - An 8.70 kg block slides with an initial speed of 1.56 m/s **down** a ...

Physics - An 8.74-kg block slides with an initial speed of 1.52 m/s down a ramp ...

Physics - 1) A car moving along a straight stretch of road at 60 mph [26.7 ...