a solution (S) is prepared by dissolving 50.0 g calcium chloride in 250 ml volumetric flask wich is then filled with distilled water up to the line mark. calculate the molar concentration of solution (S)
CaCl2 is 111 grams per mol
so 50 g is .45 moles
.45 moles / .25 L = 1.8 mol/liter
To calculate the molar concentration of the solution, we need to determine the number of moles of calcium chloride (CaCl2) present in the solution and then divide by the volume of the solution in liters.
First, we need to convert the mass of calcium chloride (50.0 g) into moles. We can do this by using the molar mass of CaCl2.
The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol. Since there are two chlorine atoms in CaCl2, we need to multiply the molar mass of chlorine by 2.
Molar mass of CaCl2 = (40.08 g/mol) + 2 * (35.45 g/mol) = 40.08 + 70.9 = 110.98 g/mol.
Now we can calculate the number of moles of CaCl2:
Number of moles = mass / molar mass
Number of moles = 50.0 g / 110.98 g/mol ≈ 0.4505 mol
Next, we need to convert the volume of the solution from milliliters (mL) to liters (L).
The volume of the solution is given as 250 mL = 250/1000 L = 0.25 L
Finally, we can calculate the molar concentration by dividing the number of moles by the volume of the solution:
Molar concentration = number of moles / volume of solution
Molar concentration = 0.4505 mol / 0.25 L = 1.802 mol/L
Therefore, the molar concentration of the solution is approximately 1.802 mol/L.