Posted by **lisa** on Sunday, March 10, 2013 at 8:52am.

solve each equation 1) log5-log2x=1 2) 2log(x+1)=5

- math -
**Reiny**, Sunday, March 10, 2013 at 9:45am
1)

log5 - log(2x) = 1

log(5/2x) = 1

5/(2x) = 10^1

20x = 5

x = 1/4

2)

2log(x+1) = 5

log(x+1) = 5/2

10^(5/2) = x+1

316.227766 = x+1

x = 315.227766

OR

log(x+1)^2 = 5

(x+1)^2 = 10^5

x+1 = ±√(10^5) , but clearly x >-1

x+1 = 316.227766..

x = 315.227766..

- math -
**Mutale**, Sunday, March 10, 2013 at 10:00am
1)> log 5 + log 2 + log x = 1

>log (5 X 2) + log x = 1

>1 + log x = 1

>log x = 0

>x = 10^0

>x = 1

#2 has me twisted.

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