Posted by **Mia** on Sunday, March 10, 2013 at 5:20am.

I cant figure this out! Can someone please tell me were my mistake is?? :)

- a man is 3 times as old as his son. In 11 years time he will be twice as old as his son will be.

Let s represent sons age in years now

I did: present man: 3s son: s

In 11 years man: 2(s+11). Son: s+11

- Math -
**Mia**, Sunday, March 10, 2013 at 5:33am
I tried alot and finally got the answer :) thanks anyways

- Math -
**Reiny**, Sunday, March 10, 2013 at 9:54am
I always found that these are easy when the information is restated in different cases

present:

son's age --- x

man' age ---- 3x

in 11 years from now:

son's age = x+11

man's age = 3x+11

it said, at that time the man is twice as old as his son

3x+11 = 2(x+11)

3x + 11 = 2x + 22

x = 11

The son is now 11, and the man is now 33

check:

now son is 11, man is 33

in 11 years:

son is 22 , man is 44

is the man twice as old as his son at that time ?

YES.

- Math -
**Anonymous**, Saturday, December 10, 2016 at 7:53am
A man is four times as old as his son. In 6 years he will be three times as old. The son present age is what?

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