Chris spent 1/4 of his money to buy shirt .He spent 1/2 of remaining money to buy shorts.Given that Chris had left $56 left. How mush money did he at first?
he spend (1/4+1/2)=3/4 of his total money.
so has remaining money=(1-3/4)=1/4 of total money.
he had total money=$58*4=$432
Let n be the amount Chris started with. After he spent 1/4, he had 3/4 n left. Then he spent 1/2 of that, leaving him with 1/2 of 3/4 n, or 3/8 n. So:
3n/8=56
3n=448
n=149.33333 as the amount Chris started with.
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To solve this problem, let's break it down step by step.
Let's assume that the amount of money Chris had initially is represented by the variable "x".
Step 1: Chris spent 1/4 of his money to buy a shirt.
This means he spent (1/4) * x on the shirt. After buying the shirt, he would have (x - (1/4)x) = (3/4)x left.
Step 2: Chris then spent 1/2 of the remaining money to buy shorts.
This means he spent (1/2) * (3/4)x = (3/8)x on shorts. After buying the shorts, he would have ((3/4)x - (3/8)x) = (3/8)x left.
Step 3: Given that Chris had $56 left.
Based on the given information, we know that (3/8)x = $56.
To find the value of x, let's solve the equation:
(3/8)x = $56
To solve for x, we multiply both sides of the equation by (8/3):
x = ($56) * (8/3)
x = $149.33 (rounded to the nearest cent)
Therefore, Chris initially had $149.33.