Post a New Question

chemistry

posted by on .

Sn (s) + 2Cl2(g) --> SnCl4(l).Sn(s) + Cl2(g) --> Sn Cl2(l) DH = -186.2 kJSnCl2(s) + Cl2(g) --> SnCl4(l) DH = -325.1 kJWhat is the change in enthalpy?

  • chemistry - ,

    Sn (s) + 2Cl2(g) --> SnCl4(l)
    Change in enthalpy = DH1 + DH2 + DH3

    Sn(s) + Cl2(g) --> Sn Cl2(l)
    DH1 = -186.2 kJ

    Sn Cl2(l) --> SnCl2(s)
    DH2 = ? <-- find this either in a table in your book or online

    SnCl2(s) + Cl2(g) --> SnCl4(l)
    DH3 = -325.1 kJ

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question