Parking in a student parking lot costs 2.00 for the first half hour and $1.75 for each hour thereafter. A partial hour is charged the same as a full hour. What is the longest time a student can park for $9.00?
Show your work.
9 - 2 = 7 >> first half hour
7/1.75 = 4
4 1/2 hours
You are an angel, thank you so much.
You're very welcome.
To find the longest time a student can park for $9.00 in a student parking lot, we can set up an equation and solve for the unknown variable.
Let's break down the cost of parking:
- The first half hour costs $2.00.
- Each subsequent hour costs $1.75.
So, the cost of parking can be expressed as:
Cost of parking = $2.00 + ($1.75 * Number of hours parked after the first half hour)
Let's assume the longest time a student can park for $9.00 is X hours. By substituting this value into the equation, we can solve for X.
$9.00 = $2.00 + ($1.75 * X)
Rearranging the equation:
$1.75X = $9.00 - $2.00
$1.75X = $7.00
Dividing both sides by $1.75 to isolate the variable X:
X = $7.00 / $1.75
X ≈ 4
Therefore, the longest time a student can park for $9.00 is approximately 4 hours.
Explanation of the steps:
1. We started by setting up an equation to represent the cost of parking based on the given information.
2. We assumed the longest time a student can park for $9.00 is X hours.
3. We substituted the value of X into the equation.
4. We simplified and isolated the variable X by performing mathematical operations.
5. We divided both sides of the equation to solve for X.
6. Finally, we found that X is approximately 4, indicating that the longest time a student can park for $9.00 is 4 hours.