the molar mass of NaOH is 40g/mol, how many grams ofNaOH are required to yield 0.65 mol?
40 grams/ 1mole = x grams/.65 mol
Cross multiply and solve for x.
61.54 g
To calculate the number of grams of NaOH required to yield 0.65 mol, you can use the formula:
Mass (g) = Number of Moles (mol) × Molar Mass (g/mol)
Given that the molar mass of NaOH is 40 g/mol and the number of moles is 0.65 mol, you can substitute these values into the formula to find the mass.
Mass (g) = 0.65 mol × 40 g/mol
Mass (g) = 26 g
Therefore, 26 grams of NaOH are required to yield 0.65 mol.
To calculate the grams of NaOH required to yield 0.65 mol, you can use the formula:
Mass (grams) = Number of moles × Molar mass
Given that the molar mass of NaOH is 40 g/mol and the desired number of moles is 0.65 mol, you can substitute these values into the formula:
Mass (grams) = 0.65 mol × 40 g/mol
Now, let's perform the calculation:
Mass (grams) = 26 g
Therefore, 26 grams of NaOH are required to yield 0.65 mol.