Posted by **Sally** on Saturday, March 9, 2013 at 4:42pm.

Consider only the discriminant, b2 - 4ac, to determine whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions. 2x2 = -2 -5

Thank you

- College Algebra -
**Dr. Jane**, Saturday, March 9, 2013 at 4:45pm
Are you missing an x?

2x^2 + 2x + 5 = 0

a = 2

b=2

c = 5

If your answer = 0 then there is only 1 real number solution.

If your answer = any positive number you will have two real solutions

If your answer = any negative number you will have two imaginary solutions.

All of the above happens because in the quadratic equation you take +/- the square root of b^2-4ac

- College Algebra -
**Daphne**, Wednesday, March 13, 2013 at 1:23am
What is the commutative law of addition to find an expressoon equivalent to 5m + 9n

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