which equation represents a line with slope -2 and passes through(-1,5)?
how do you do this?
so the answer is 2x-y=3?
There are a couple ways to do this problem.
One way:
y-y1 = m(x-x1)
y - 5 = -2(x - (-1)
y - 5 = -2(x+1)
y = -2x -2 +5
y = -2x +3
To find the equation of a line with a given slope and a point it passes through, we can use the point-slope form of a linear equation.
The point-slope form of a linear equation is: y - y1 = m(x - x1)
where (x1, y1) represents the coordinates of the given point on the line, and m represents the slope.
In this case, the slope is -2 and the point it passes through is (-1,5). Plugging these values into the point-slope form equation, we get:
y - 5 = -2(x - (-1))
Simplifying further:
y - 5 = -2(x + 1)
Now, to convert this equation into slope-intercept form (y = mx + b) where b represents the y-intercept, we can distribute the -2:
y - 5 = -2x - 2
Next, we isolate y by adding 5 to both sides of the equation:
y = -2x + 3
So, the equation of the line with a slope of -2 and passing through the point (-1,5) is y = -2x + 3.