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December 22, 2014

December 22, 2014

Posted by **lisa** on Saturday, March 9, 2013 at 3:08pm.

f′(c)=f(6)−f(4)6−4

with c between 4 and 6. Approximate c to within two decimal places; we're asking you to approximate c, because you can't "solve" for c.

- calculus -
**Reiny**, Saturday, March 9, 2013 at 8:47pmYour statement of

f′(c)=f(6)−f(4)6−4

desperately needs brackets to say

f′(c)= ( f(6)−f(4) )/(6−4)

f(6) = e^36 = 4.31123x10^15 , rather large

f(4) = e^16 = only 8886110.52

( f(6) - f(4) )/2 = 2.1556x10^15

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