Posted by **Mary** on Saturday, March 9, 2013 at 2:46pm.

Find the minimum and maximum values of the function f(x)= 2/3 sin pix on the interval [1,2] (domain).

I got (1.5, -2/3) as the minimum and no maximum on the interval. Is it correct? Thank you.

- Absolute Extrema -
**bobpursley**, Saturday, March 9, 2013 at 2:56pm
correct.

- Absolute Extrema -
**Damon**, Saturday, March 9, 2013 at 2:58pm
I bet you mean

f(x) = (2/3) sin(pi x)

f'(x) = (2/3) pi cos(pi x)

f'(x) = 0 for max or min

that is when cos (pi x) = 0

x = 1/2 and x = 3/2

if x = 1/2

y = (2/3)sin (pi/2) = 2/3

if x = 3/2

y = (2/3) sin (3 pi/2) = -2/3

PS

You can be sure that the max and min of a sin function are +1 and -1

- Absolute Extrema -
**Damon**, Saturday, March 9, 2013 at 3:00pm
sorry, x = 1/2 not in domain so you are right

- Absolute Extrema -
**Mary**, Saturday, March 9, 2013 at 3:20pm
Thank you both! I appreciate it. :)

## Answer this Question

## Related Questions

- Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...
- Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum values...
- Calculus - Find the absolute maximum and absolute minimum values of the function...
- Please check my Calculus - 1. Find all points of inflection: f(x)=1/12x^4-2x^2+...
- Caluclus - Find the absolute maximum and absolute minimum of f on the interval...
- calculus - there are no examples of this type of problem in my book so if you ...
- Calculus - Find the absolute extrema of the function on the interval [2, 9]. (...
- calculus - 2) Let g(s)= t(4−t)^1/2 on the interval [0,2]. Find the ...
- Please check my Calculus - 1. Which of the following describes the behavior of f...
- Relative Extrema: AP Calculus - Consider the function f(x)= (3/4)x^4-x^3-3x^2+6x...