Posted by **Mary** on Saturday, March 9, 2013 at 2:46pm.

Find the minimum and maximum values of the function f(x)= 2/3 sin pix on the interval [1,2] (domain).

I got (1.5, -2/3) as the minimum and no maximum on the interval. Is it correct? Thank you.

- Absolute Extrema -
**bobpursley**, Saturday, March 9, 2013 at 2:56pm
correct.

- Absolute Extrema -
**Damon**, Saturday, March 9, 2013 at 2:58pm
I bet you mean

f(x) = (2/3) sin(pi x)

f'(x) = (2/3) pi cos(pi x)

f'(x) = 0 for max or min

that is when cos (pi x) = 0

x = 1/2 and x = 3/2

if x = 1/2

y = (2/3)sin (pi/2) = 2/3

if x = 3/2

y = (2/3) sin (3 pi/2) = -2/3

PS

You can be sure that the max and min of a sin function are +1 and -1

- Absolute Extrema -
**Damon**, Saturday, March 9, 2013 at 3:00pm
sorry, x = 1/2 not in domain so you are right

- Absolute Extrema -
**Mary**, Saturday, March 9, 2013 at 3:20pm
Thank you both! I appreciate it. :)

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