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Chemistry

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At a certain temperature, the equilibrium constant, Kc, for this reaction is 53.3.

H2(g)+I2(g) <--> 2HI(g)

Kc= 53.3

At this temperature, 0.300 mol of H2 and 0.300 mol of I2 were placed in a 1.00-L container to react. What concentration of HI is present at equilibrium?

HI = ? M

Please post an answer too if possible.

  • Chemistry -

    0.300mol/1.00L = 0.300M
    ..........H2 + I2 ==> 2HI
    I......0.300..0.300....0
    C.........-x....-x.....+2x
    E.....0.300-x..0.300-x..2x

    Substitute the E line into Kc expression and solve for x. Remember HI is 2x.

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