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Posted by on Friday, March 8, 2013 at 9:41pm.

∫1(3e^x+3x^2 )dx
0

  • calculus - , Friday, March 8, 2013 at 10:11pm

    I guess you mean integral from 0 to one

    [ 3 e^x + x^3 ] at x = 1 - at x = 0

    at x = 1
    3 e^1 + 1 = 3e+1

    at x = 0
    3 e^0 + 0 = 3

    so in the end
    3 e - 2

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