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posted by MIKE9999 on Friday, March 8, 2013 at 9:41pm.
∫1(3e^x+3x^2 )dx 0
I guess you mean integral from 0 to one [ 3 e^x + x^3 ] at x = 1 - at x = 0 at x = 1 3 e^1 + 1 = 3e+1 at x = 0 3 e^0 + 0 = 3 so in the end 3 e - 2
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