∫1(3e^x+3x^2 )dx
0
I guess you mean integral from 0 to one
[ 3 e^x + x^3 ] at x = 1 - at x = 0
at x = 1
3 e^1 + 1 = 3e+1
at x = 0
3 e^0 + 0 = 3
so in the end
3 e - 2
0
[ 3 e^x + x^3 ] at x = 1 - at x = 0
at x = 1
3 e^1 + 1 = 3e+1
at x = 0
3 e^0 + 0 = 3
so in the end
3 e - 2