Posted by Steve on Friday, March 8, 2013 at 6:34pm.
Two identical +9.5uF point charges are initially 3.5cm from each other.
If they are released at the same instant from rest, how fast will each be moving when they are very far away from each other? Assume they have identical masses of 2.0mg

physics  bobpursley, Friday, March 8, 2013 at 6:42pm
Here is one way to do this.
I assume you are in calculus. Lets pretend we can do this charge by charge.
First charge:
work done=INT force dx from x=.03 to inf
where force=kq2q1/x^2
integrate it over that domain of x.
So that is the energy this partical has.
SEcond charge.
Now, with the first charge is gone, the second charge doesn't move.
So the total work in the system is what we figured on the first charge. So if both particles were released, this energy would have been divided evenly, so now we know the KE of each particle
KE=1/2 work done above
1/2 m v^2=1/2 work done above
solve for v

physics  Steve, Friday, March 8, 2013 at 6:45pm
I am not in calculus. Is there any other way to to this through algebra?!

physics  Damon, Friday, March 8, 2013 at 6:53pm
calculate potential energy when close to each other.
You probably have the formula which Bob Pursley just told you how to derive with calculus by integrating the force
it is something like
U = k Q1 Q2 / R
The (1/2)m v^2 of each particle is half of that
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