Posted by Steve on Friday, March 8, 2013 at 6:34pm.
Here is one way to do this.
I assume you are in calculus. Lets pretend we can do this charge by charge.
First charge:
work done=INT force dx from x=.03 to inf
where force=kq2q1/x^2
integrate it over that domain of x.
So that is the energy this partical has.
SEcond charge.
Now, with the first charge is gone, the second charge doesn't move.
So the total work in the system is what we figured on the first charge. So if both particles were released, this energy would have been divided evenly, so now we know the KE of each particle
KE=1/2 work done above
1/2 m v^2=1/2 work done above
solve for v
I am not in calculus. Is there any other way to to this through algebra?!
calculate potential energy when close to each other.
You probably have the formula which Bob Pursley just told you how to derive with calculus by integrating the force
it is something like
U = k Q1 Q2 / R
The (1/2)m v^2 of each particle is half of that
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