A net force of 5.75 * 103 N [180degree�] acts on

a mass of 23.0 kg. If, while the force acts,
the mass travels through a displacement of
360 m [210 degree�], what work did the net force
do on the object? Into what form of energy
was this work transferred?

To calculate the work done by the net force on the object, you can use the equation:

Work = Force * Distance * cosθ

Where:
- Work is the work done (in joules)
- Force is the net force acting on the object (in newtons)
- Distance is the displacement of the object (in meters)
- θ is the angle between the force and displacement vectors

In this case, the given values are:
- Net force = 5.75 * 10^3 N [180°]
- Mass = 23.0 kg
- Displacement = 360 m [210°]

To find the force acting on the object, you can use Newton's second law:

Net force = mass * acceleration

Since the mass and acceleration are not given directly, we need to find them. The acceleration can be obtained using another equation:

Acceleration = Net force / mass

The direction of acceleration will be the same as the direction of the net force vector, which is 180 degrees.

Next, we can calculate the acceleration and force:

Acceleration = (5.75 * 10^3 N) / 23.0 kg
Acceleration ≈ 250.0 m/s^2

Net force = (23.0 kg) * (250.0 m/s^2)
Net force = 5750 kg*m/s^2 = 5750 N

Now that we have the force and displacement, we can calculate the work done:

Work = (5750 N) * (360 m) * cos(210°)

To calculate cos(210°), you need to convert the angle to radians:
cos(210°) = cos((210 * π) / 180)

Now you can calculate the work done:

Work = (5750 N) * (360 m) * cos((210 * π) / 180)

The answer to the first part of your question, which is the work done by the net force on the object, can be found by evaluating this equation.

Regarding the second part of your question, the work done is transferred into the form of energy known as mechanical energy. Mechanical energy consists of both kinetic energy (energy of motion) and potential energy (energy due to position or elevation).

W = 5750[180o] * 360[210o]=2.07*10^6 J.

@ 390o = 2.07*10^6 J. @ 30o.