Posted by **tmouery** on Friday, March 8, 2013 at 11:04am.

A swimming pool is in the form of a semicircular figure. Its width is 20 ft. and that parallel portions of the sides are each 20 ft. What is the are of a 5-ft-wide walk surrounding the pool? Round to the tenths.

- business math -
**Steve**, Friday, March 8, 2013 at 11:35am
what "sides" of a semicircle are parallel? Do you mean the circle has a diameter of 20 ft? If the base is 20 ft, then that would be the diameter of the circle.

Assuming that, we have a pool with area 1/2 pi * 10^2 = 50pi ft^2

Increase the radius by 5 ft, and you have an area of 1/2 pi * 15^2 = 225/2 pi

So, the area of the walk is 125/2 pi = 196.4 ft^2

If I have interpreted the dimensions incorrectly, fix my error and redo the calculation.

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