The area of a rectangular floor is 8x+6x-20. The width of the desktop is 2x+4. What is the length of the floor?

if it is then the length would be 4x-5

you just factor it out of the 8x^2+6x-20 since they already give you the other factor which is 2x+4

was the 8x suppose to be 8x^2??

Yes sorry about that

The length of a rectangle is 5ft greater that 4 times its width the area is 369 sq ft. Whats the lenght?

To find the length of the floor, we need to divide the area by the width.

Given:
Area of the rectangular floor = 8x + 6x - 20
Width of the desktop = 2x + 4

We can express the length of the floor as:

Length of the floor = (Area of the rectangular floor) / (Width of the desktop)

Substituting the given values:

Length of the floor = (8x + 6x - 20) / (2x + 4)

To simplify the expression, let's combine the like terms in the numerator:

Length of the floor = (14x - 20) / (2x + 4)

And if we further simplify the expression, we can divide both terms in the numerator by a common factor of 2:

Length of the floor = 2(7x - 10) / (2x + 4)

Therefore, the length of the floor is 2(7x - 10) / (2x + 4).