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March 30, 2015

March 30, 2015

Posted by **Sam** on Thursday, March 7, 2013 at 8:13pm.

building that is 80 meters tall. (Vo = 0)Fortunately, the stuntman is attached

to a cable that is wrapped around a flywheel (massive spool), with a radius of 0.5m. If the man takes 8 seconds to reach the ground:

(a) what is the moment of inertia of the flywheel?

(b) What is the moment inertia if the radius of the wheel was 1m?

(c) What is the mass of the flywheel in each case?

- Physics -
**Damon**, Thursday, March 7, 2013 at 8:24pmKe of man = (1/2) m v^2

Ke of flywheel = (1/2) I w^2 = (1/2)I (v/r)^2

Total Ke = (1/2) m v^2 + (1/2) (I/r^2)v^2

potential energy decrease = m g h = 90(9.81)(80) = 70,632 Joules

constant acceleration

average v = 80 meters/8 seconds = 10 m/s

initial v is zero so final v is 20 m/s

so

70,632 = (1/2)(20)^2 [ m + I/r^2 ]

I think you can take it from there.

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