Homework Help: Physics

Posted by Jalen on Thursday, March 7, 2013 at 7:15pm.

A ball of mass 0.3 kg, initially at rest, is projected from ground level toward a wall that is 27.0 m away. The ball's velocity the moment it is projected is 75.0 m/s at 60° relative to the horizontal, and the wall is 11.0 m high. During its flight, the ball impacts nothing else and is not subjected to air resistance.

Physics - Damon, Thursday, March 7, 2013 at 7:24pm
Vi = 75 sin 60 = 65 m/s
u = 75 cos 60 = 37.5 m/s

to go 27 m horizontal takes
t = 27/37.5 = .72 seconds

How high will it be (I assume that is the question) ?

v = Vi - 9.8 t
h = 0 + Vi t - 4.9 t^2
h at .72 s = 65(.72) - 4.9 (.72)^2
= 44.25 m high

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