Thursday

March 5, 2015

March 5, 2015

Posted by **sw** on Thursday, March 7, 2013 at 5:22pm.

x+4y=8

-x-4y= -8

choose which one this problem fit in

1)the system has no solution

2) the system has a unique solution (x,y)=

or the system has a infinitely many solutions they must satisfy the following equation: y=

- math -
**Ms. Sue**, Thursday, March 7, 2013 at 5:27pmx = 8 - 4y

8 - 4y - 4y = -8

-8y = -16

y = 2

-x-4y= -8

-x -8 = -8

- math -
**Dr. Jane**, Thursday, March 7, 2013 at 5:49pmfor some reason when I am adding the two equations, I am getting 0 = 0. This is a true statement which means that there is an infinite number of solutions. Any x,y pair that works in one will work in the other.

- math -
**Ms. Sue**, Thursday, March 7, 2013 at 6:05pmYou're right, Dr. Jane. I hadn't intended to post my answer -- but I guess my finger slipped.

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