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August 29, 2014

August 29, 2014

Posted by **Dee** on Thursday, March 7, 2013 at 12:39pm.

f(x) = x^4/5, a = 32

- Cal 1 -
**Steve**, Thursday, March 7, 2013 at 2:19pmAssuming you mean x^(4/5), else x^4 is huge at x=32,

f(32) = 16

f' = 4/5 x^(-1/5)

f'(32) = 4/5 * 1/2 = 2/5

So, now you have a point (32,16) and a slope (2/5). What's the line?

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