Posted by Dee on Thursday, March 7, 2013 at 12:39pm.
Find the linearization L(x) of the function at a.
f(x) = x^4/5, a = 32

Cal 1  Steve, Thursday, March 7, 2013 at 2:19pm
Assuming you mean x^(4/5), else x^4 is huge at x=32,
f(32) = 16
f' = 4/5 x^(1/5)
f'(32) = 4/5 * 1/2 = 2/5
So, now you have a point (32,16) and a slope (2/5). What's the line?