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Posted by on Thursday, March 7, 2013 at 12:39pm.

Find the linearization L(x) of the function at a.
f(x) = x^4/5, a = 32

  • Cal 1 - , Thursday, March 7, 2013 at 2:19pm

    Assuming you mean x^(4/5), else x^4 is huge at x=32,

    f(32) = 16
    f' = 4/5 x^(-1/5)
    f'(32) = 4/5 * 1/2 = 2/5

    So, now you have a point (32,16) and a slope (2/5). What's the line?

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