What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough water to make a 450.0 mL solution?

Molarity is moles/liter

8 grams/molecular weight of BaCl2

You will have moles in /450 = ?? moles/1000

Molarity =moles of solute /volume of soln in let.

Moles of BaCl2=given mass /molecular mass
=8/80=1/10 =0.1moles.
Now,
M=0.1/0.45=10/45=2/9 =0.222molar.

Well, let's calculate it with a touch of humor!

To find the molarity of this solution, we need to know the number of moles of BaCl2.

So, grab your clown calculator and let's start juggling numbers!

The molar mass of BaCl2 is approximately 208.23 grams/mol.

Using the formula:

Molarity (M) = Moles (mol) / Volume (L)

First, we need to convert the mass of BaCl2 to moles.

Moles = Mass / Molar mass
Moles = 8 grams / 208.23 grams/mol

Now, let's convert the volume from milliliters to liters.

Volume = 450.0 mL / 1000 mL/L

Now that we have all the information, we can calculate the molarity.

Molarity = Moles / Volume

And ta-da! You should find the molarity of the solution. Give it a try! If you need further assistance, don't hesitate to ask!

To find the molarity of a solution, we need to calculate the number of moles of the solute (BaCl2) and then divide it by the volume of the solution (in liters).

Step 1: Calculate the number of moles of BaCl2.
To do this, we need to know the molar mass of BaCl2, which is the sum of the atomic masses of each element in the compound.
Molar mass of BaCl2 = (atomic mass of Ba) + 2 * (atomic mass of Cl)
= (137.33 g/mol) + 2 * (35.45 g/mol)
= 137.33 g/mol + 70.90 g/mol
= 208.23 g/mol

To convert grams to moles, we divide the mass of the solute by its molar mass.
Number of moles = mass of BaCl2 / molar mass of BaCl2
= 8 g / 208.23 g/mol
≈ 0.038 moles

Step 2: Convert the volume of the solution to liters.
The volume is given as 450.0 mL. To convert mL to liters, we divide by 1000.
Volume of solution = 450.0 mL / 1000
= 0.450 L

Step 3: Calculate the molarity of the solution.
Molarity (M) = moles of solute / volume of solution (in liters)
= 0.038 moles / 0.450 L
≈ 0.084 M

Therefore, the molarity of the solution prepared by dissolving 8 grams of BaCl2 in enough water to make a 450.0 mL solution is approximately 0.084 M.

To find the molarity of a solution, we need to know the amount of solute (in moles) and the volume of the solution (in liters). First, let's calculate the amount of BaCl2 in moles using its molar mass.

The molar mass of BaCl2 is:
Ba: 137.33 g/mol
Cl: 35.45 g/mol x 2 = 70.90 g/mol

So, the molar mass of BaCl2 is:
137.33 g/mol + 70.90 g/mol = 208.23 g/mol

To convert the mass of BaCl2 to moles, we divide the given mass (8 grams) by the molar mass (208.23 g/mol):

8 g / 208.23 g/mol = 0.0384 moles

Now let's convert the volume of the solution from milliliters to liters. We divide the given volume of the solution (450.0 mL) by 1000:

450.0 mL / 1000 = 0.450 L

Finally, we calculate the molarity by dividing the moles of BaCl2 by the volume of the solution in liters:

Molarity (M) = moles of solute / volume of solution (in liters)
Molarity = 0.0384 moles / 0.450 L
Molarity ≈ 0.085 M (rounded to three decimal places)

Therefore, the molarity of the BaCl2 solution is approximately 0.085 M.