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Algebra

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Rectangle ABCD has an area of 72 units squared. The length of BF is 4 units. Algebracially prove that the sum of the areas of triangles CBF and ADF are equal to 36 units squared.

  • Algebra - ,

    Where is F ?

  • Algebra - ,

    BF is between BA

  • Algebra - ,

    BA is shorter side of rectangle

  • Algebra - REINY - ,

    Hi - Do you think this is correct?

    BC = AD
    Area of Rectangle = (FB+AF).BC
    Area of Rectangle = 72 units squared

    Area = 1/2 bh
    Area 1 = 1/2 FB.BC
    Area 2 = 1/2 AF.AD
    1/2 = AF.BC

    A1 + A2 = 36 units squared

    1/2 FB.BC + 1/2 AF.BC
    1/2 [FB.BC + AF.BC]
    1/2 [BC (FB + AF)
    1/2.72 units squared - 36 units squared

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