Posted by jonh on Thursday, March 7, 2013 at 12:37am.
Assuming you meant
f(x) = √((x)(x-4))
f'(x) = (x-2)/√((x)(x-4))
So, x=2 is the critical value
except that f(x) is not defined for 0<x<4
If you meant f(x) as written,
f'(x) = (3x-4)/(2√x)
and the critical value is x = 4/3
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