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April 1, 2015

April 1, 2015

Posted by **Anonymous** on Wednesday, March 6, 2013 at 10:14pm.

- Calculus -
**Reiny**, Thursday, March 7, 2013 at 10:00amI think you want to find dy/dt

or else we don't need the fact that

dx/dt = 15 ft/s

x^2 + y^2 = 65^2

2x dx/dt + 2y dy/dx= 0

dy/dx = (-2x dx/dt)/(2y) = (-x dx/dt)/y

so for the given data

dy/dt = -39(15)/52 = -45/4 or -11.25 ft/s

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