Post a New Question

Calculus

posted by on .

Find relative maxima and minima of
g(x)= 2x^2+ 4000/x +10

  • Calculus - ,

    g ' (x) = 4x - 4000/x^2 + 0
    = 0 for a max/min

    4x = 4000/x^2
    4x^3 = 4000
    x^3 = 1000
    x = 10

    when x = 10
    f(10) = 200 + 400 + 10 = 610

    there is a relative min 610 at x=10

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question