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January 27, 2015

January 27, 2015

Posted by **Cam** on Wednesday, March 6, 2013 at 10:09pm.

g(x)= 2x^2+ 4000/x +10

- Calculus -
**Reiny**, Thursday, March 7, 2013 at 9:44amg ' (x) = 4x - 4000/x^2 + 0

= 0 for a max/min

4x = 4000/x^2

4x^3 = 4000

x^3 = 1000

x = 10

when x = 10

f(10) = 200 + 400 + 10 = 610

there is a relative min 610 at x=10

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