The height of a parallelogram is 5 feet more than its base. If the area of the parallelogram is 204 square feet, find its base and height.

base of a ||gm is

base x height

base --- x
height --- x+5
s(x+5) = 204
x^2 + 5x - 204 = 0
(x-12)(x+17) = 0
x = 12 or a negative

base is 12, height is 17

Well, finding the base and height of a parallelogram is not as challenging as telling a joke in clown shoes! But let's see what we can do.

Let's call the base of the parallelogram "b" and the height "h". We know that the height is 5 feet more than the base, so we can write the equation h = b + 5.

The formula for the area of a parallelogram is A = bh, where A is the area, b is the base, and h is the height. We know that the area of the parallelogram is 204 square feet, so we can write the equation 204 = bh.

Now we can substitute h = b + 5 into the area equation:
204 = b(b + 5).

Expanding this out:
204 = b^2 + 5b.

Rearranging the equation:
b^2 + 5b - 204 = 0.

Now we have a quadratic equation to solve. But don't worry, we don't need any clown tricks for this. We can either factor or use the quadratic formula to find the value of b. Once we find the value of b, we can substitute it back into h = b + 5 to find the value of h.

And there you have it, the base and height of the parallelogram, without any clowning around!

To find the base and height of the parallelogram, we can use the formula for the area of a parallelogram, which is given by:

Area = base * height

Let's denote the base of the parallelogram as "b" and the height as "h".

We are given that the height of the parallelogram is 5 feet more than its base, so we can write:

h = b + 5

We are also given that the area of the parallelogram is 204 square feet, so we can write:

204 = b * h

Substituting the expression for h from the first equation into the second equation, we get:

204 = b * (b + 5)

Expanding and rearranging the equation, we have:

b^2 + 5b = 204

Rearranging this equation into a quadratic equation form, we have:

b^2 + 5b - 204 = 0

To solve this quadratic equation, we can either factor it or use the quadratic formula. Since the coefficient of b^2 is 1, we can try factoring.

We need to find two numbers whose sum is 5 and product is -204. After some experimentation, we find that the numbers are 12 and -17:

(b - 12)(b + 17) = 0

Setting each factor equal to zero, we get two possible values for b:

b - 12 = 0 --> b = 12

b + 17 = 0 --> b = -17 (discard this solution since we are dealing with lengths)

So the base of the parallelogram is 12 feet.

Substituting this value back into the equation h = b + 5, we find:

h = 12 + 5 = 17

Therefore, the height of the parallelogram is 17 feet.

In conclusion, the base of the parallelogram is 12 feet, and the height is 17 feet.

How long is the base of a parallelogram with an area of 84 square feet and a height of 12 feet

base of a ||gm is

base x height

base --- x
height --- x+5
s(x+5) = 204
x^2 + 5x - 204 = 0
(x-12)(x+17) = 0
x = 12 or a negative

base is 12, height is 17