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How many milliliters of 0.762 M H3PO4 are required to react with 243 mL of 0.159 M Ba(OH)2 if the products are barium phosphate and water?

  • chem -

    3Ba(OH)2 + 2H3PO4 ==> Ba3(PO4)2 + 6H2O

    mols Ba(OH)2 = M x L = ?
    Convert mols Ba(OH)2 to mols H3PO4 using the coefficients in the balanced equation.
    The M H3PO4 = mols H3PO4/L H3PO4. YOu know mols H3PO4 and M H3PO4, solve for L H3PO4 and convert to mL.

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