Sunday

March 1, 2015

March 1, 2015

Posted by **Beth** on Wednesday, March 6, 2013 at 5:09pm.

Here's the problem: Helen painted a picture that was 10 inches longer than it was wide. When she framed the picture, the outside dimensions (that is, the length and the width) were each two inches longer. If the area of the picture with the frame was 40 sq inches more than the area of the picture without its frame, what was the length of the original painting?

Any help you could provide would be greatly appreciated!

- Math -
**Steve**, Wednesday, March 6, 2013 at 5:14pmlength = w+10

(w+2)(w+10+2) = w(w+10)+40

w = 4

check:

picture: 4x14 = 56

total : 6*16 = 96 = 56+40

**Answer this Question**

**Related Questions**

Math - Hello there! Could You please help me with this Geometry word problem? ...

basic geometry - The length of a rectangular picture is seven iches longer than ...

algebra - A rectangular picture is 2 inches longer than it is wide. When a frame...

Algebra - A rectangular picture is 4 inches longer than it is wide. The picture ...

Math - Need some help on a word problem. It has a storage chest. The dimensions ...

problem solving - Erica painted a picture of her dog. The picture has an area of...

Geometry word problem - A rectangular pond is 10m longer than it is wide. A walk...

Math Word Problem - Please help with this math word problem: Jamal has a 5X7 ...

Math - Brandy plans to frame a picture with a sheet of construction paper. Her ...

Math - erica painted a picture of her dog the picture has an area of 3,600 cm2 ...