Posted by Dylan on Wednesday, March 6, 2013 at 4:09pm.
Find constants a and b in the function f(x)=axe^(bX) such that f(1/8)=1 and the function has a local maximum at x=1/8.

Calculus  Steve, Wednesday, March 6, 2013 at 5:00pm
f = ax e^(bx)
f' = ae^(bx) + abx e^(bx)
= ae^(bx) (1+bx)
f'(1/8) = 0, so b = 8
f(1/8) = 1 = a(1/8)e^(1), so a=8e
f(x) = (8e)x e^(8x)

Calculus  Anonymous, Thursday, November 6, 2014 at 10:50am
Calculus  Steve, Wednesday, March 6, 2013 at 5:00pm
f = ax e^(bx)
f' = ae^(bx) + abx e^(bx)
= ae^(bx) (1+bx)
f'(1/8) = 0, so b = 8
f(1/8) = 1 = a(1/8)e^(1), so a=8e
f(x) = (8e)x e^(8x)

Calculus  Anonymous, Monday, November 7, 2016 at 11:53pm
you suck steve
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