a man pushes a lawnmower of mass 50kg at a constant velocity over a horizontal lawn.he exerts a push of 200n on the handle a t angle of 60 to the horizontal..Dertemime the vertical componet of this force and determine the horizontal component of this force
To determine the vertical and horizontal components of the force exerted by the man pushing the lawnmower, we can use some basic trigonometry.
The vertical component of the force can be found using the formula:
Vertical Component = Force * sin(Angle)
In this case, the force is 200 N and the angle is 60 degrees. Let's calculate the vertical component:
Vertical Component = 200 N * sin(60°)
Vertical Component = 200 N * (√3/2)
Vertical Component = 200 N * 1.732/2
Vertical Component = 200 N * 0.866
Vertical Component = 173.2 N (approx)
Therefore, the vertical component of the force exerted by the man on the lawnmower is approximately 173.2 N.
Now, let's calculate the horizontal component of the force using the formula:
Horizontal Component = Force * cos(Angle)
In this case, the force is 200 N and the angle is 60 degrees. Let's calculate the horizontal component:
Horizontal Component = 200 N * cos(60°)
Horizontal Component = 200 N * (1/2)
Horizontal Component = 100 N
Therefore, the horizontal component of the force exerted by the man on the lawnmower is 100 N.
To determine the vertical and horizontal components of the force, we can use trigonometry.
Given:
Mass of the lawnmower, m = 50 kg
Force applied by the man, F = 200 N
Angle, θ = 60°
Vertical Component:
The vertical component of the force is equal to F * sin(θ).
Vertical component = 200 N * sin(60°)
Vertical component = 200 N * 0.866
Vertical component = 173.2 N
Horizontal Component:
The horizontal component of the force is equal to F * cos(θ).
Horizontal component = 200 N * cos(60°)
Horizontal component = 200 N * 0.5
Horizontal component = 100 N
Therefore, the vertical component of the force is 173.2 N and the horizontal component of the force is 100 N.