Monday

December 22, 2014

December 22, 2014

Posted by **Mary** on Wednesday, March 6, 2013 at 1:10pm.

I came up with this so far:

x + y = 15

xy^2 is the maximum

derivative of xy^2= 2xyy' + y^2

Now how do I solve this ^ after I set it to zero? I am stuck on that. Thank you so much

- Calculus Optimization Problem -
**Dr. Jane**, Wednesday, March 6, 2013 at 1:13pmYou need to substitute

y = 15-x

x(15-x)^2

x(225 -30x+x^2)

225x -30x^2 + x^3

Now you can take the derivative and set it equal to zero.

- Calculus Optimization Problem -
**Mary**, Wednesday, March 6, 2013 at 1:19pmThank you! I solved it out, and I got x=5 and y= 10 with a product of 500. Is this correct

- Calculus Optimization Problem -
**Dr. Jane**, Wednesday, March 6, 2013 at 1:30pmI agree. You are welcome.

**Answer this Question**

**Related Questions**

pre-calculus - THe sume of 2 positive numbers is 20. Find the two numbers such ...

arithmetic - 1. The first and last term of an A.P are, a and l respectively, ...

Calculus - Find two positive numbers whose sum is 8 such hat when the cube of th...

arithmetic - 1. The first and last term of an A.P are, a and l respectively, ...

calculus - find two positive integers such that the sum of the first number and ...

calculus - Find two positive numbers whose product is 100 and whose sum is a ...

pre-calculus - Find two rational numbers such that the difference is 3 times the...

calculus - find 3 positive real numbers whose sum is 500 and whose product is as...

Calculus - Find two positive numbers that satisfy the requirements: "The product...

Calculus - Find two positive numbers that satisfy the given requirements. The ...