At present a woman is twice as old as her daughhter, twenty one years ago she was 3 times older than her daughter
Hint: ket x be the daughters current age
First we represent the unknowns:
Let x = daughter's present age
Let 2x = mother's present age
According to the problem, 20 years ago, the mother was three times older than her daughter. Thus,
2x - 20 = 3(x - 20)
Solving for x,
2x - 20 = 3x - 60
2x - 3x = -60 + 20
-x = -40
x = 40 years old (daughter, present age)
2x = 80 years old (mother, present age)
hope this helps~ :)
thankss alot :D
Actually it was 21 years ago...
But i get it thanks :)
To solve this problem, let's follow the given hint and represent the daughter's current age as "x."
Now, we know that the woman is currently twice as old as her daughter, so the woman's current age would be 2x.
Now, let's consider the information provided 21 years ago. We need to subtract 21 from the current ages to find their ages at that time.
According to the given information, 21 years ago, the woman's age was three times the age of her daughter. So, we can write the equation as:
(2x - 21) = 3(x - 21)
Now, we can solve this equation to find the value of "x," which represents the daughter's current age.
Expanding the equation:
2x - 21 = 3x - 63
Rearranging the equation:
3x - 2x = 63 - 21
x = 42
Therefore, the daughter's current age is 42.