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Math

posted by on .

At present a woman is twice as old as her daughhter, twenty one years ago she was 3 times older than her daughter
Hint: ket x be the daughters current age

  • Math - ,

    First we represent the unknowns:
    Let x = daughter's present age
    Let 2x = mother's present age

    According to the problem, 20 years ago, the mother was three times older than her daughter. Thus,
    2x - 20 = 3(x - 20)
    Solving for x,
    2x - 20 = 3x - 60
    2x - 3x = -60 + 20
    -x = -40
    x = 40 years old (daughter, present age)
    2x = 80 years old (mother, present age)

    hope this helps~ :)

  • Math - ,

    thankss alot :D

  • Math - ,

    Actually it was 21 years ago...

  • Math - ,

    But i get it thanks :)

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