Posted by **Heleny** on Wednesday, March 6, 2013 at 8:31am.

At present a woman is twice as old as her daughhter, twenty one years ago she was 3 times older than her daughter

Hint: ket x be the daughters current age

- Math -
**Jai**, Wednesday, March 6, 2013 at 8:35am
First we represent the unknowns:

Let x = daughter's present age

Let 2x = mother's present age

According to the problem, 20 years ago, the mother was three times older than her daughter. Thus,

2x - 20 = 3(x - 20)

Solving for x,

2x - 20 = 3x - 60

2x - 3x = -60 + 20

-x = -40

x = 40 years old (daughter, present age)

2x = 80 years old (mother, present age)

hope this helps~ :)

- Math -
**Heleny**, Wednesday, March 6, 2013 at 8:54am
thankss alot :D

- Math -
**Heleny**, Wednesday, March 6, 2013 at 8:55am
Actually it was 21 years ago...

- Math -
**Heleny**, Wednesday, March 6, 2013 at 8:56am
But i get it thanks :)

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