four times the sum of a number and two increased by three is at least twenty seven
4(x+2) + 3 >= 27
.
To solve this equation, let's break it down step by step:
1. Let's start by identifying the number in the equation. Let's call the number "x".
2. The sum of a number and two is expressed as "x + 2".
3. Four times the sum of a number and two is "4(x + 2)".
4. The equation states that four times the sum of a number and two increased by three is at least twenty-seven. Mathematically, we can express this as:
4(x + 2) + 3 ≥ 27
Now, to solve the equation:
5. Start by simplifying the left side of the equation:
4(x + 2) + 3 = 4x + 8 + 3
= 4x + 11
6. Now, we have the equation:
4x + 11 ≥ 27
7. To isolate x, let's subtract 11 from both sides of the equation:
4x + 11 - 11 ≥ 27 - 11
4x ≥ 16
8. Finally, divide both sides of the equation by 4:
(4x)/4 ≥ 16/4
x ≥ 4
Therefore, the solution to the equation is x ≥ 4. This means that any number equal to or greater than 4 will satisfy the inequality given in the question.