If 15gram of potassium trioxochlorate V is heated in the presence of MnO2.What is the mass of chloride produce?
To calculate the mass of chloride produced when 15 grams of potassium trioxochlorate V reacts with MnO2, you need to determine the balanced chemical equation for the reaction.
The formula for potassium trioxochlorate V is KClO3. When it reacts with MnO2 (manganese(IV) dioxide), it forms potassium chloride (KCl) and oxygen gas (O2) as the products. The balanced chemical equation is:
2KClO3 + MnO2 -> 2KCl + 3O2
From the balanced equation, you can see that 2 moles of KClO3 produce 2 moles of KCl. This means the mole ratio of KClO3 to KCl is 1:1.
To calculate the mass of KCl produced, you first need to find the number of moles of KClO3. The molar mass of KClO3 can be calculated as follows:
KClO3 = (1 mol K) + (1 mol Cl) + (3 mol O) = 39.1 g + 35.5 g + 48 g = 122.6 g/mol
The number of moles of KClO3 is then determined by dividing the mass (15 g) by the molar mass (122.6 g/mol):
moles of KClO3 = 15 g / 122.6 g/mol = 0.1224 mol
Since the mole ratio of KClO3 to KCl is 1:1, the number of moles of KCl produced is also 0.1224 mol.
Finally, to calculate the mass of KCl produced, you multiply the number of moles by the molar mass of KCl:
mass of KCl = 0.1224 mol * (39.1 g KCl/mol) = 4.80 grams
Therefore, the mass of chloride produced is 4.80 grams.