Posted by Katie on Tuesday, March 5, 2013 at 10:59pm.
6^(2log(x)) = 8
- math - Steve, Tuesday, March 5, 2013 at 11:19pm
assuming logs base 10,
2logx = log_6(8)
logx = 1/2 log_6(8)
x = √(10^(log_6(8))
now log_6(8) = log6/log8. so
x = √(10^log6)^(1/log8)
- math - Reiny, Tuesday, March 5, 2013 at 11:19pm
take log of both sides
log [ 6^(2logx) ] = log8
2logx (log6) = log8
2logx = log8/log6
log x^2= log8/log6
x = √( 10^(log8/log6) ) = 3.804339012
check using your calculator, it works
- math - go with Reiny - Steve, Wednesday, March 6, 2013 at 3:34pm
Go with Reiny's answer. I messed up my log base conversion.
Answer this Question
More Related Questions
- Math - Express as a single logarithm. 1/2log(subscript)3 144-log(subscript)3 4+...
- algebra - equivalent expression for 2log(x+1)-2log(x-1)-log(x-1)
- Precalculus - What am I doing wrong? I keep getting 48 and its wrong... Solve ...
- algebra - does log base of 4 sqrt(t/s)=1/2log base of 4 t - 1/2log base of 4s? ...
- math - 2log[base3]9 = ?
- math - solve for x 32^x+5=16^2x+1 1/2log(x+2)=2 sqrt(2x-3)-2=5
- math - how do you Solve 2log x-log 3=2 pls help
- Math - Are you allowed to do this 2log(x-1) =log(x+1) 2 (x-1)=(x+1) x=3 Please ...
- math - Given that x = 2log t is a solution of the equation10^(2x+1) -7(10^x) -26...
- math - solve each equation 1) log5-log2x=1 2) 2log(x+1)=5