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March 1, 2015

March 1, 2015

Posted by **Anonymous** on Tuesday, March 5, 2013 at 10:57pm.

- calculus -
**Damon**, Wednesday, March 6, 2013 at 3:09amfrom point 1 to point 2 dy = 0, y = 0 and x goes from 0 to 2

so integral one = ∮[(4x^2+3x)dx =(4/3)x^3 + (3/2)x^2 = 32/3+6 = 50/3

from point 2 to point 3, dx = 0 , x = 2 and y from 0 to 2

so integral 2 = ∮(34+3y)dy] from 0 to 2

similar for the last two lines, then add the results. Remember direction for example for integal 3 y does not change but x is from 2 to 0, not 0 to 2

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