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January 30, 2015

January 30, 2015

Posted by **sam** on Tuesday, March 5, 2013 at 9:56pm.

- Math -
**Ms. Sue**, Tuesday, March 5, 2013 at 9:58pmYour problem states that there are 6 dancers.

Do you need to know how many dances there will be?

- Math -
**sam**, Tuesday, March 5, 2013 at 10:02pmYes how many dances

- Math -
**Ms. Sue**, Tuesday, March 5, 2013 at 10:08pmThere should be 15 dances.

- Math -
**ellis**, Tuesday, March 5, 2013 at 10:15pmms.sue could you please answer my question i previousl posted

- Math -
**sam**, Tuesday, March 5, 2013 at 10:29pmHow did you come up with that #?

- Math -
**Ms. Sue**, Tuesday, March 5, 2013 at 10:35pmDancer 1 dances with dancers 2, 3, 4, 5, 6

2: 3, 4, 5, 6,

3: 4, 5, 6

4: 5, 6

5: 6

- Math -
**sam**, Tuesday, March 5, 2013 at 10:47pmUnderstood thanks!

- Math -
**Ms. Sue**, Tuesday, March 5, 2013 at 10:54pmYou're welcome.

- Math -
**Damon**, Wednesday, March 6, 2013 at 3:17amcombinations of 5 taken 2 at a time

c(5,2) = 5!/[3!*2!] = 5*2 = 10

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