posted by Anonymous .
The electrons in a beam are moving at 2.8 ×
108 m/s in an electric ﬁeld of 17000 N/C.
What value must the magnetic ﬁeld have if
the electrons pass through the crossed ﬁelds
Answer in units of µT
q v B = q E, therefore
B = E/v
If E is in N/C and v is in m/s, the B field will be in Teslas