Posted by kim on Tuesday, March 5, 2013 at 9:47pm.
Try a one-sample t-test since the sample size is fairly small. This will be a one-tailed test (the alternate hypothesis will show a specific direction). Formula for a one-sample t-test is the following:
z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size)
With your data:
z = (620 - 614)/(36/√16) = ?
I'll let you finish the calculation.
There are t-tables that show values for one-tailed and two-tailed tests. If n = 16, degrees of freedom would be n - 1, which is 15. Check the critical value from the table using degrees of freedom for a one-tailed test at .05 level of significance. Compare that value you find from the table to your t-test statistic calculated above. If the t-test statistic exceeds the critical value from the t-table, reject the null. If the t-test statistic does not exceed the critical value from the t-table, do not reject the null. Draw your conclusions from there.
I hope this helps.
Related Questions
statistics - The typical American generates about 3.8 pounds of solid trash per ...
Statistics - The typical American generates about 3.8 pounds of solid trash per ...
statistic - The mean salary per day of all the 5000 employees who work in a ...
statistics - Among coffee drinkers, men drink a mean of 2.8 cups per day with a ...
statistics - A widget factory's worker productivity is normally distributed...
Statistics - Is this right? and how can I break it down if needed? A factory&#...
ap chemistry - A 1.50 liter tank filled with helium at 125 atm is used to fill ...
math (statistics) - Suppose you are looking for a job. You interview with a ...
Statistics - Working of a problem--I have found the mean, variance and the ...
Statistics - Working of a problem--I have found the mean, variance and the ...
For Further Reading
