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January 30, 2015

January 30, 2015

Posted by **ellis** on Tuesday, March 5, 2013 at 9:40pm.

- PLEASE help urgent -
**ellis**, Tuesday, March 5, 2013 at 10:01pmplease

- math hw -
**Reiny**, Tuesday, March 5, 2013 at 10:54pmarea of first = length1 x width

15 = length1 x width

width = 15/length1

area of 2nd:

16 = length2 x width

width = 16/length2

so length2/length1 = 16/15

the length of the first is 15, its width is 1

the length of the 2nd is 16, its width is 1

the largest value of the width has to be 1

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