math hw
posted by ellis on .
the areas of two rectangles are 15 square inches and 16 square inches. the length and width of both figures are whole numbers. if the rectangles have the same width, what is the greatest possible value for their widths? please show work

please

area of first = length1 x width
15 = length1 x width
width = 15/length1
area of 2nd:
16 = length2 x width
width = 16/length2
so length2/length1 = 16/15
the length of the first is 15, its width is 1
the length of the 2nd is 16, its width is 1
the largest value of the width has to be 1